Calculating Exposure Compensation for Very Wide Lens & Tilt

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I am using a SuperAngulon 58 mm XL in the 6 x 9 format (with a Horseman). I understand the basic principle of how to calculate exposure compensation (i.e. if the lens is 25% further away from the film plane than it would be if focused at infinity, you need to make a 1/2 stop exposure correction). With the 58 mm, however, it starts off very close to the film plane. Thus, when I use significant amounts of front or rear tilt, the upper and lower halves of the image will require different exposures. . . . Is there any way around this problem?

-- Howard Slavitt (nverdesoto@earthlink.net), April 27, 1999

Answers

Howard, is this a theorectical question or is it a real problem? Have you tried a center weighted filter?

-- Ellis Vener (evphoto@insync.net), April 27, 1999.

Or a graduated neutral density filter?

-- Ellis Vener (evphoto@insync.net), April 27, 1999.

...or dodging and burning the final print? ;^D>

-- Doremus Scudder (ScudderLandreth@compuserve.com), April 30, 1999.

What you're going to find is that with a lens that wide (for that format) the max camera movements you will be using will very tiny

-- C MATTER (cmatter@riag.com), May 06, 1999.

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